Paul's age is equal to the square of the sum of the ages of his two daughters. four years from now,the difference between his age and his daughters ages will be twenty six years. find his present age.
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Sum of two Daughter's age = a
Paul's age = a²
After 4years
daughter's age = a + 8
Paul's age = a² + 4
a² + 4 - 2a - 8 = 26
a² - a - 30 = 0
a² - 6a + 5a - 30 = 0
a(a-6) + 5(a-6)
(a +5) (a-6)
a = -5, 6
Age can't be -ve.
So daughters age = 6
Father's age = 36 (a² = 6²)
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