Question

Paul sold 20% of wheat and 12 kg of sugar. If he had 9 kg of wheat and 20 kg of sugar what
percentage of his stock did he sell in total?​

Answer 1

Answer:

47.59 %

Step-by-step explanation:

1) Calculate how much stock Paul had at the beginning :

9+20=29 kg

2) Calculate how much wheat Paul sold in kg:

0.2*9=1.8 kg

3) Calculate how much stock Paul sold in total:

1.8+12=13.8 kg

4) Calculate the stock he sold in percent:

13.8/29*100=47.59 %

Answer 2

Answer:

47.58% of total stock is sold by Paul.

Step-by-step explanation:

Given that :

• Paul sold 20% of wheat and 12 kg of sugar
• Paul has total 9 kg of wheat and 29 kg of sugar

To find :

• Total percentage of stock he sells

Solution :

• Paul sells 20% of total wheat he had. Since, Paul had 9 kg of wheat.
• Stock of wheat sold by Paul is

$20 \: percent \: of \: 9kg \: of \: wheat = \frac{20}{100} \times 9 \\ = \frac{9}{5} kg$

• Total stock sold by Paul = 9/5 kg of wheat + 12 kg of sugar = 69/5 kg.
• Total stock Paul had = 9 kg of wheat + 20 kg of sugar = 29 kg of total stock.
• Let, Percentage of stock sold by Paul is x%. Then,

$\frac{x}{100} \times 29 = \frac{69}{5} \\ x = \frac{69 \times 20}{29 } \\x = \frac{1380}{29} \\ x = 47.58 \: percent$

• Hence, 47.58% of total stock is sold by Paul.