Question

Paul starts driving his car at 20kmph reaches his office 5 min late had he driven 50% faster on an average he would have reached 5 min earlier than the scheduled tike how far is his office?

Answer 1

Answer:

distance = distance

speed 1× time 1 = speed2×time 2

20× (x + 1/12) = 30× (x -1/12)

20x + 20/12 = 30x - 30/12

50/12 = 10x

x = 50/120

x =5/12

put this value

20×(5/12+1/12)

20×1/2

=10km