Math, asked by tomba4532, 11 months ago

Paulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.1 0.10, point, 1. The probability of her getting injured playing soccer is 1 10 10 1 ​ start fraction, 1, divided by, 10, end fraction.

Answers

Answered by Swarup1998
6

Complete question: Paulina plays both volleyball and soccer. The probability of her getting injured playing volleyball is 0.1. The probability of her getting injured playing soccer is 1/10. Which of these events is more likely?

Solution:

  • 'More likely' means to have the probability of occurrence of one event more than the other events.

While polling volleyball, probability of getting hurt is

P(A) = 0.1

and in the case of soccer, it is

P(B) = 1/10

i.e., P(B) = 0.1

Here we see, P(A) = P(B)

Answer: We can conclude that no event is more likely to occur than the other, i.e., the probability of occurrence for each event is equally likely.

Answered by meghana1308
2

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