Math, asked by pawan5994, 1 year ago

Pawan is a cashier in a bank. He has currency notes of denominators 1000, 500 and 100 respectively. The ratio of the number of these notes is 2:3:5. If the total cash with Pawan is rupees 5,00,000 how many notes of rupees 1000 denomination does he have?​

Answers

Answered by arun135094
2

Answer:

100 denomination notes

Step-by-step explanation:

Given Ratio of Currency notes =

2:3:5

Total parts = 10 Parts

Denominations are ₹1000, ₹500, ₹100

Total Rupees = ₹5,00,000

No. of ₹100 Denomination notes

= ₹5,00,000×5/10×₹100

= 25,00,000/1000

= 2,500 Denomination notes

No. of ₹500 Denomination notes

= ₹5,00,000×3/10×₹500

= 15,00,000/5,000

= 300 Denomination Notes

No. of ₹1000 DenominationNotes

= ₹5,00,000×2/10×₹1,000

= 10,00,000/10,000

= 100 denomination notes

Answered by rijularoy16
13

Answer:

250 notes.

Step-by-step explanation:

Given that the denomination notes of 1000, 500 and 100 are in the ratio 2:3:5.

Number of 1000 denomination notes with Pawan = 2x.

Therefore, amount = ₹2000x.

Number of 500 denomination notes with Pawan = 3x.

Therefore, amount = ₹1500x.

Number of 100 denomination notes with Pawan = 5x.

Therefore, amount = ₹500x.

Total amount = ₹500000.

According to question,

2000x + 1500x + 500x = 500000

=) 4000x = 500000

=) x = 50000 / 4000

=) x = 125.

Therefore, number of 1000 denomination notes = 2x = 2 × 125 = 250 notes.

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