Physics, asked by swasthibhat, 9 months ago

Pawan Travels at a constant speed of 32 metre per second for 5 seconds it begins to accelerate at a rate of 3 metre per second square for seven seconds and then maintains that speed for another 18 seconds finally it slows down to rest in 22 seconds how far did Van travel during the course of the entire problem​

Answers

Answered by TPS
6

Explanation:

first part:

Pawan Travels at a constant speed of 32 metre per second for 5 seconds

u = 32 m/s

t = 5 s

distance travelled = ut= 32×5 = 160m

second part:

it begins to accelerate at a rate of 3 metre per second square for seven seconds

u = 32 m/s

a = 3 m/s^2

t = 7 s

distance travelled = ut + 1/2 at^2 = 32×7 + 1/2 × 3 × 7^2 = 224 + 73.5 = 297.5 m

third part:

then maintains that speed for another 18 seconds

v = u + at = 32 + 3×7 = 53 m/s

t = 18 s

distance travelled = vt = 53×18 = 954m

fourth part

finally it slows down to rest in 22 seconds

u = 53 m/s

v = 0

t = 22s

a = (v-u)/t = -53/22 m/s^2

distance travelled = (v^2 - u^2) / 2a

= (0 - 53^2 ) / ( 2 × -53/22)

= 53×53 / (53/11)

= 53×11 = 583m

Total distance travelled = 160+297.5+954+583 m


TPS: add to get the final answer.
swasthibhat: thanks a lot
Anonymous: Perfect explanation bhai
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