Math, asked by jattjssinghaulakh, 1 year ago

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PLEASE ANSWER!!!!!

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Answers

Answered by anr4u97
3
This is ur answer. Hope u understood
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jattjssinghaulakh: hey please give me one favour please answer another question of mine
Answered by ashmitkumar2
3

hey \: here \: is \: your \: answer
A can finish a work in 8days
work done by A in 1 day =
 \frac{1}{8}
B can finish a work in 10 days
work done by B in 1 day =
 \frac{1}{10}
C can finish a work in 16days
work done by C in 1 day =
 \frac{1}{16}
work done by ( B + C ) in 1 day =
 \frac{1}{10}   +  \frac{1}{16}
=
 \frac{13}{80}
work done by ( B + C ) in 4 days =
4 \times \frac{13}{80}
=
 \frac{13}{20}

remaining work =
1 -  \frac{13}{20}
=
 \frac{7}{20}
work done by A + B in 1 days =
 \frac{1}{8}  +  \frac{1}{10}
=
 \frac{9}{40}
remaining work done by ( A + B ) =
 \frac{7}{20}  \div  \frac{9}{40}
=
 \frac{14}{9}


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jattjssinghaulakh: please answer another question of mine
ashmitkumar2: ok i give but plz mark me
jattjssinghaulakh: first answer
ashmitkumar2: okay give : )
jattjssinghaulakh: see one of my question like this starting with Attention
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