Payal is 5 years older than Proma . If four more than four times Proma's age is three less than three times Payal's age , what are their ages?
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Hi ,
Let Proma's age = x years
Payal's age = ( x + 5 ) years
Four times of Proma's age = 4x years
Three times of Payal's age = 3( x+ 5 )
= 3x + 15
According to the problem ,
If four more than four times of
Proma's age is three less than
threetimes of Payal's age.
4x + 4 = 3x + 15 - 3
4x - 3x = 15 -3 - 4
x = 15 - 7
x = 8
Therefore ,
Proma's age = x = 8 years
Payal's age = ( x + 5 ) years
= ( 8 + 5 ) years
= 13 years.
I hope this helps you.
****
Let Proma's age = x years
Payal's age = ( x + 5 ) years
Four times of Proma's age = 4x years
Three times of Payal's age = 3( x+ 5 )
= 3x + 15
According to the problem ,
If four more than four times of
Proma's age is three less than
threetimes of Payal's age.
4x + 4 = 3x + 15 - 3
4x - 3x = 15 -3 - 4
x = 15 - 7
x = 8
Therefore ,
Proma's age = x = 8 years
Payal's age = ( x + 5 ) years
= ( 8 + 5 ) years
= 13 years.
I hope this helps you.
****
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