PB and QA are perpendicular to segment AB. If PO= 4cm, QO=7cm and area of triangle POB=80cm². Find the area of triangle QOA
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Answer:
In △OAQ and △OBP, we have
∠A=∠B [Each equal to 90
∘
]
∠AOQ=∠BOP
So, by AA-criterion of similarity, we have
△AOQ∼△BOP
⇒
Area(BOP)
Area(△AOQ)
=
OP
2
OQ
2
⇒
150
Area(△AOQ)
=
52
7 2
⇒ Area(△AOQ)=
2549
×150cm 2
=294cm 2
Step-by-step explanation:
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