Pbe a point inside a circle having centre O and radius 10 cm. If OP = 4 and APB be a chord of circle through P, then find the value of PA PB.
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Given info : P be a point inside a circle having centre O and radius 10 cm. If OP = 4 and APB be a chord of circle through P.
To find : the value of PA and PB.
solution : we know, a line drawn from centre of circle is the perpendicular bisector of chord.
so, OP is perpendicular bisector of AB.
now, ∆OPB [ see figure ]
from Pythagoras theorem,
OB² = OP² + PB²
⇒(10cm)² = (4cm)² + PB²
⇒100 - 16 = PB²
⇒PB² = 84
⇒PB = 2√21 cm
∵ PA = PB [ OP divided chord into two equal parts ]
Therefore, PA = PB = 2√21 cm
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