Question

PC15, PC13 and Cl2 are at equilibrium at 500 K in a closed container and
their concentrations are 0.8 x 10-3 molL-1, 1.2 x 10-3 mol Lland1.2 x 10-3 mol L-1
If decomposition is depicted as PC15(g) =PC13(g) + Cl2(g) AH°=124.0kJ/mol
What will be the value of Kc for the reaction?
What will be the value of Kc for the reverse reaction at the same temperature?
What would be the effect on Kc if temperature is increased​

Answer 1

Answer:

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Step-by-step explanation:

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