Question

PCI5, PCI3, Cl2, are at equilibrium
at 500K and having
concentrations 1.59 M for PCI3,
1.59M for Cl2, and 1.41M for
PCI5, then 'Kc' for
PCl3(g) +Cl2(e) = PCI5
​

Answer 1

Answer:

The given reaction is :-

PCl5(g)⇌PCl3(g)+Cl2(g)

KC=[PCl5][PCl3][Cl2]

       =0.8×10−31.2×10−3×1.2×10−3=1.8×10−3molL−1

Explanation:

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