Question

pcl5 gives pcl3+Cl2 give the relation between kp and kc​

Answer 1

KP=KC[RT]power delta N.

Explanation:

pcl5=pcl3+cl2

delta N is gaseous products-gaseous reactants.so 2-1=1.

kp=kc [RT] power 1.we know that

if n is positive then kp>kc,kp<kc If n is negative and kp=kc if n is 0. so answer is kp>kc.

Answer 2

The relation between 'Kp' and 'Kc' for the reaction PCl₅ → PCl₃ + Cl₂ is given as Kp = (Kc)(RT).

Given:

Reaction: PCl₅ → PCl₃ + Cl₂

To Find:

The relation between 'Kp' and 'Kc'.

Solution:

→ 'Kp' and 'Kc' are the equilibrium constants for a given gaseous mixture. The 'Kp' and 'Kc' for a given equilibrium remain constant at a given temperature.

→ The 'Kc' is the equilibrium constant in terms of concentrations, where all the concentrations are at equilibrium and are expressed in moles/Liter.

→ The 'Kp' is the equilibrium constant in terms of partial pressure. It is defined for the equilibrium reaction which contains gaseous component. If a component other than gas is present the its active mass must be one.

→ Hence, while calculating the 'Kp' we take the partial pressures of each gas into consideration. But while calculating the 'Kc' we take the molar concentrations of each gas into consideration.

→ The relationship between 'Kp' and 'Kc' is given as:

                                       $K_{p} =K_{c} (RT)^{\triangle n}$

Here 'Δn' is equal to the difference in the number of moles of gaseous product and the number of moles of gaseous reactant. Hence we can say that:

  ∴ Δn = (Number of Moles of Product) - (Number of Moles of Reactant)

→ For the reaction: PCl₅(g) → PCl₃(g) + Cl₂(g)

                                  ∴ Δn = (1 +1) - 1 = 2 - 1 = 1

                                  ∴ Δn = 1

→ Hence for the reaction, relationship between 'Kp' and 'Kc' would be given as:

                                         Kp = Kc (RT)¹

                                       ∴ Kp = Kc (RT)

So the relation between 'Kp' and 'Kc' for the reaction PCl₅ → PCl₃ + Cl₂ is given as Kp = (Kc)(RT).

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