Question

PCl5=PCl3+Cl2 . The given reaction is started with certain qualitity of PCl5 . At equilibrium the mole fraction of Cl2 formed is 0.25 and total equilibrium pressure is 4atm . Determine partial pressure of PCl3 at equilibrium.

Answer 1

Answer:

3 atm

Explanation:

partial pressure =mole fraction ×total pressure

p.p. of Cl2=0.25×4

=1atm

P.P. of PCl3=total pressure -p.p. of Cl2

=4-1

=3 atm

Answer 2

3 is your answer

p=x*P =0.25*4=1