Question

PD formula ky ha bolo​

Answer 1

Answer:

The dimensional formula of potential difference is given by,

[M1 L2 T-3 I-1]

Where,

M = Mass

I = Current

L = Length

T = Time

Derivation

Potential Difference = work done × [charge]-1 . . . . (1)

Since, Work done = Force (M × a) × Displacement . . . (2)

And, the dimensional formula of,

Mass = [M1 L0 T0] . . . . (3)

Displacement = [M0 L1 T0] . . . . (4)

Acceleration = [M0 L1 T-2] . . . . . (5)

On substituting equation (3), (4) and (5) in equation (2) we get,

Work done = [M1 L0 T0] × [M0 L1 T-2] × [M0 L1 T0]

∴ The dimensions of Work done = [M1 L2 T-2] . . . . (6)

Since, Charge = Current × time

∴ The dimensional formula of charge = [M0 L0 T1 I1] . . . . (7)

On substituting equation (6) and (7) in equation (1) we get,

Potential Difference = work done × [charge]-1

Or, P.D = [M1 L2 T-2] × [M0 L0 T1 I1]-1 = [M1 L2 T-3 I-1] .