Question

PE
3. calculate the mass of product of the O2 when
30g of the reacts with asg of co? and
end out the limiting reagent​

Answer 1

Answer:

SWER

2C(s) + O2. -----> CO(g)

2mol. 1mol. 2mol

24g. 32g. 56g

Let carbon be completely consumed.

24g carbon give 56 g CO.

Let O2 is completely consumed. 

∵ 32 g O2 give 56 g CO.

∴ 96 g O2 Will give 32/56×96gCO=168gCO

Since, carbon gives least amount of product, te.,56 g CO or 2 mole CO, hence carbon will be the limiting reactant. 

∴ Excess reactant is O2. 

Amount of O2 used =56−24=32g 

Amount of O2 left =96−32=64g

 32g O2 react with 24 g carbon 

∴ 96 g O2 will react with 72g carbon. 

Thus, carbon should be taken 72g so that nothing is left at the end of the reaction.

Explanation:

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