Question

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4. Solve the following riddle:
I am a number,
Tell my identity!
Take me seven times over
And add a fifty!
To reach a triple century
You still need forty!

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Answer 1

$\LARGE{ \underline{ \blue{ \sf{Required \: answer:}}}}$

Now it's time to solve a riddle. We have to identify the number for which several hints are given in the riddle.

I am a number,

Tell my identity!

• Let the number be x

Take me seven times over

And add a fifty!

• 7 times x will be 7x
• Adding 50 = 7x + 50

To reach a triple century

You still need forty!

Here, it is saying that to reach 300, we still need to add a 40. That means, the result of the previous step is 300 - 40 = 260. So, we can write it as:

⇛ 7x + 50 = 260

⇛ 7x = 210

⇛ x = 210 / 70

⇛ x = 30

Thus the number asked in the riddle is 30.

And we are done!

Answer 2

Let the number be y

━━━━━━━━━━━━━━

Given:

• seven times over me

= 7y

━━━━━━━━━━

• And add a fifty

= 7y + 50

━━━━━━━━━━

• To reach a triple century you'll still need a forty

Triple century means 300,

you need more 40 to get a triple century! So add 40 with (7y+50)

━━━━━━━━━━

7y+50+ 40 = 300

⟹ 7y + 90 = 300

⟹ 7y = 300 - 90

⟹ 7y = 210

⟹ $\red{\bold{\boxed{\large{y = 30}}}}$

Thus the number is 30.