Question

PE =4cm, QE=4.5cm, PF=8cm and RF=9cm.​

Answer 1

Answer:

then qr = 6.5 cm............,,........

Answer 2

Answer:

(ii)Given: PE = 4 cm, QE = 4.5 cm, PF = 8 cm and RF = 9 cm

Now, = cm

And cm

Therefore, EF divides the sides PQ and PR of PQR in the same ratio.

EF is parallel to QR.