Question

Pea plant having round seeds and violet flowers is crossed with another pea plant having wrinkled seeds and white flowers : (a) Name the kind of cross. (b) Which law is explained by above cross? (c) Draw a cross showing phenotypic ratio of F2 generation​

Answer 1

Answer:

When we see the phenotype of the two types of progeny we find that both the types have the seed colour yellow while approximately 50% of them have round seed type while the other 50% have wrinkled seed type. So, the pea plant with yellow and round seeds must be homozygous for yellow seed colour (YY) while it must be heterozygous for the round seed type (Rr).

So, the genotype of the plant with yellow and round seed is YYRr.

So, the correct answer is 'YYRr'

Answer 2

Answer:

(a) For 50% violet flowers, the genotype will be Vv and vv. The cross is shown above.

(b) Since only one character inheritance is being studied at one time, this type of cross is called monohybrid cross. This cross explains the law of segregation where the alleles of the parental pair segregate from each other and only one allele is transmitted to a gamete. The segregation is a random process such that there is a 50 percent chance of a gamete containing either allele.

(c) Snapdragon shows incomplete dominance in which the dominant gene is not completely able to suppress the effect of the recessive gene. This results in a third phenotype.

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