Question

pebble of mass 0.05 kg is thrown vertically upwards. Give the

direction and magnitude of the net force on it during its upwards

motion.​

Answer 1

Answer:

1. When the pebble is moving upward the force acting on it is gravitational force in downward direction. F = mg = 0.05 × 10 = 0.5 N

1. When the pebble is moving upward the force acting on it is gravitational force in downward direction. F = mg = 0.05 × 10 = 0.5 N 2. Even in this case F = mg = 0.5 N in downward direction.

1. When the pebble is moving upward the force acting on it is gravitational force in downward direction. F = mg = 0.05 × 10 = 0.5 N 2. Even in this case F = mg = 0.5 N in downward direction. 3. Since there is no force other than gravitational force acting on pebble, during the whole process F = mg = 0.5 N. Note that pebble moves in opposite direction because of its initial velocity. The situation remains same for pebble thrown at an angle.

Answer 2

mass=0.05kg

acceleration=10m/s(g)

Force=ma

=0.05×10

=0.5N