Question

Pedro wants to buy some shirts over the Internet. Each shirt costs $10.01 and has a shipping cost of $9.94 per order. If Pedro wants to spend no more than $70 for his shirts, which inequality shows the maximum number of shirts, p, that he can buy? 9.94 + 10.01p ≤ 70, so p ≤ 6 9.94 − 10.01p ≤ 70, so p ≤ 7 9.94p + 10.01p ≤ 70, so p ≤ 8 9.94p − 10.01p ≤ 70 ≤ 60, so p ≤ 9

Answer 1

Hey Mate!!

This is the answer

because p = the number of shirts pedro can buy without pushing $70,  

10.01p is the cost of the shirts alone.

For any number of shirts, there is a $9.94 shipping price, which we add onto what we have so far:

10.01p+9.94

because pedro can spend "no more than $70", we will use a less than or equal to inequality symbol.

10.01p + 9.94  < 70

If we want to simplify that to find what p is, then we subtract 9.94 from both sides of the inequality:

10.01p < 60.06

now we divide both sides by 10.01 and we get

p < 6

And if it needs to be precise, we can do

0 < p < 6

that shows that p is not a negative number

Bye✨

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

Pedro wants to buy some shirts over the Internet. Each shirt costs $10.01 and has a shipping cost of $9.94 per order. If Pedro wants to spend no more than $70 for his shirts, which inequality shows the maximum number of shirts, p, that he can buy

• 9.94 + 10.01p ≤ 70, so p ≤ 6

• 9.94 − 10.01p ≤ 70, so p ≤ 7

• 9.94p + 10.01p ≤ 70, so p ≤ 8

• 9.94p − 10.01p ≤ 70 ≤ 60, so p ≤ 9

EVALUATION

The maximum number of shirts Pedro can buy = p

Now Each shirt costs $10.01

Price of p shirts = $ 10.01p

Again it has a shipping cost of $9.94 per order

So total amount to be spend for p shirts

= $ ( 9.94 + 10.01p)

Since Pedro wants to spend no more than $70 for his shirts

So by the given condition

9.94 + 10.01p ≤ 70

We now solve for p

$\sf 9.94 + 10.01p \leqslant 70$

$\sf \implies \: 10.01p \leqslant 70 - 9.94$

$\sf \implies \: 10.01p \leqslant 60.06$

$\sf \implies \: p \leqslant 6$

FINAL ANSWER

Hence the correct option is

9.94 + 10.01p ≤ 70, so p ≤ 6

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