Question

Peggy is 37 years old, and her son is eight. In how many years will Peggy be exactly twice as old as her son?

Answer 1

Answer:

after 66 years his son can double the age of his father

son age 8

father age is 37

,37-8=29-----1

29+37=66

Answer 2

Answer:

Step-by-step explanation:

Let the number of years be x.

Peggy's age after x years = 37+x

Her son's age after x years = 8+x

∴ (37+x) = 2(8+x)

37 + x = 16 + 2x

2x - x = 37-16

x = 21