Question

pen-men=87 ,boy-can= how GIVE LOGIC A,,256 B,,,,345,,,C,,,,169,,,D,,,318

Answer 1

$\underline{\underline{\mathbb{\red{\: \: SOLUTION\: \:}}}}$➡

$\underline {\bold{ \: In \: \: first \: case \: \: \: }} \\ \\ \boxed{ \bold{ \: \: PEN - MEN = 87 \: \: }}$

$\bold{P = 16 \: \: no. \: \: letter \: \: of \: \:english \: \: alphabet} \\ \\ \bold{E= 5 \: \: no \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{N = 14 \: \: no \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{M = 13 \: \: no \: \: letter \: \: of \: \: english \: \: alphabet}$

$\bold{We \: \: can \: \: assume \: \: that,} \\ \\ \bold{P = 16} \\ \bold{ E= 5} \\ \bold{N = 14} \\ \bold{ M= 13} \\ \\ \bold{So,} \\ \\ \bold{(PEN - MEN = 87 )\: \: \: can \: be \: \: wriiten \: \: as} \\ \\ \bold{(16x + 5x + 14x) - (13x + 5x + 14x = 87} \\ \\ \bold{ = > 35x - 32x = 87} \\ \\ \bold{ = > 3x = 87} \\ \\ \bold{ = > x = \frac{87}{3} } \\ \\ \bold{ = > x = 29} \\ \\ \\ \bold{Now,} \\ \\\underline{ \bold{\: \:In \: \: second \: \: case\: \:}} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\bold{ \: \: BOY- CAN = ?\: \: \: \: }}$

$\bold{B= 2 \: \: no. \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{O= 15 \: \: no. \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{Y= 25 \: \: no. \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{C= 3 \: \: no. \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{A = 1\: \: no. \: \: letter \: \: of \: \: english \: \: alphabet} \\ \\ \bold{N= 14 \: \: no. \: \: letter \: \: of \: \: english \: \: alphabet}$

$\bold{We \: \: can \: \: assume \: that,} \\ \\ \bold{B = 2} \\ \bold{O = 15} \\ \bold{Y = 25} \\ \bold{C = 3}\\ \bold{A= 1} \\ \bold{N = 14} \\ \\ \\ \bold{Now,} \\ \\ \\ \: \bold{(BOY- CAN )\: \: \: can \: \: be \: \: written \: \: as} \\ \\ \bold{BOY - CAN} \\ \\ \bold{ = (2x + 15x + 25x) - (3x + 1x + 14x)} \\ \\ \bold{ = 42x - 18x} \\ \\ \bold{ = 24x} \\ \\ \bold{In \: \: first \: \: case ,\: \: we \: \: find \: \: that } \\ \\ \boxed{\bold{ \: x = 29 \: }} \\ \\ \bold{So,} \\ \\ \bold{Putting \: \: the \: \: value \: \: of \: \: \:x \: \: \: in } \\ \\ \underline{\bold{ \: \: BOY- CAN = 24x \: \: } } \: \: \: \: \bold{ We \: \: get ,}\\ \\ \bold{BOY- CAN = 24 \times (29)} \\ \\ \bold{ = >BOY - CAN = 696 }$

$\underline{\underline{\mathbb{\red{\: \:ANSWER\: \:}}}}$➡$\boxed{\boxed{ \bold{ \purple{ BOY - CAN = 696 }}}}$

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✝$\mathfrak{\red{THANKS..}}$✝