Question

pendulum A oscillates 14 oscillations in 5 seconds and pendulum B oscillates 10 oscillations in 3 seconds.Which has a higher frequency ? Express the frequency in hertz.

Answer 1

Pendulum A
14 oscillations in 5 seconds
No. of oscillations in 1 second = 2.8 Hz
Frequency = 2.8 Hz

Pendulum B
10 oscillations in 3 seconds
No. of oscillations in 1 second = 3.33 Hz
Frequency = 3.33 Hz

∴ Pendulum B has higher frequency

Answer 2

Given:

• Pendulum A oscillates 14 times in 5 seconds.
• Pendulum B oscillates 10 times in 3 seconds.

To find:

• Which pendulum has higher frequency ?
• Express the value in hertz

Calculation:

First of all, let's define frequency :

• Frequency is defined as the number of oscillations completed in 1 second.

• The SI UNIT of frequency is per second (also known as Hertz )

For pendulum A :

$frequency = \dfrac{no. \: of \: oscillations}{time}$

$\implies frequency = \dfrac{14}{5}$

$\implies frequency = 2.8 \: hz$

For pendulum B :

$frequency = \dfrac{no. \: of \: oscillations}{time}$

$\implies frequency = \dfrac{10}{3}$

$\implies frequency = 3.33 \: hz$

So, pendulum B has higher frequency.