Question

Penny Hofstadter has a beaker of 10 liters capacity and is full of Romulan Ale. 2 liters of Romulan Ale is removed and the container is then refilled to the brim by wine. This process is repeated 2 times again. Find the amount of Romulan Ale in the container.​

Answer 1

Answer:

4 Litres Romulan Ale will be left in the beaker .And the left 6 liters will be Brim by wine

Answer 2

Answer:

Step-by-step explanation:

It is given that Penny Hofstadter has a beaker of ten liters capacity and is full of Romulan Ale.

Two liters of Romulan Ale is removed and the container is then refilled to the brim by wine.

This process is repeated twice again, in total thrice again.

In first step, if two liters are remove, Romulan Ale remained is $8l$. $2l$ wine is added.

Second Step:

If same procedure is repeated, we are left with $6.4l$ Romulan Ale and $1.8$$l$ is left.

Third Step:

We will be left with $0.8*6.4=5.12l$ of Romulan Ale in container.
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