Question

per second, what will be the horizontal distance of the fly from
The tip of his fishing rod is
bore the surface of the water
Wyat the end of the string rests
water 3.6 m away from him and
of the rod. Assuming that the
from the tip of his rod to the fly) is taut, how much string does
out (see the adjoining figure)? If he pulls in the string at the rate
AD
2/
AB= 2ADP + BC
doing fly-fishing in a
from the point directly under
1.8 m
MA
A
2.4 m
1.2 m
er 12 seconds?​

Answer 1

Answer: wish i could help

Step-by-step explanation:

Answer 2

Answer:

Ans. I. To find The length of AC.

By Pythagoras theorem,

AC2 = (2.4)2 + (1.8)2

AC2 = 5.76 + 3.24 = 9.00

AC = 3 m

Length of string she has out= 3 m

Length of the string pulled at the rate of 5 cm/sec in 12 seconds

= (5 x 12) cm = 60 cm = 0.60 m

Remaining string left out = 3 – 0.6 = 2.4 m

II. To find: The length of PB

PB2 = PC2 – BC2

= (2.4)2 – (1.8)2

= 5.76 – 3.24 = 2.52

PB = = 1.59 (approx.)

Hence, the horizontal distance of the fly from Nazima after 12 seconds

= 1.59 + 1.2 = 2.79 m (approx.)