Question

per unes 783, ind is bar and
3. Find the area of the triangle whose sides are 42 cm, cand 20 cm
length. Hence, find the height corresponding to the longest​

Answer 1

${\red{\overbrace{\underbrace{\bf{\bigstar Solution : \:\bigstar}}}}}$

$<font color = blue>$

a = 42cm

b = 42 cm

c = 20cm

using herons formula $\longrightarrow$

$s \longrightarrow semi perimeter$

semi perimeter = 42 + 42 + 20cm/2

= 104cm/2

= 52cm

area = $\sqrt{s (s - a)(s - b)(s - c)}$

area = $\sqrt{ 52(52- 42)(52 - 42)(52 - 20)}$

area = $\sqrt{ 52 × 10 × 10 × 32}$

area = $\sqrt{ 166,400}$

1/2 × base × height = $407.92$

20cm × height = $407.92 × 2$

20cm × height = $815.84$

height = 815.84/20

height = 40.79cm

${\orange{\underline{\underline{\bf{\bigstar\:\: height : 40.79cm \:\:\bigstar}}}}}$

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area of triangle = 1/2 × base × height

= 1/2 × 20cm × 40.79cm

= 1/2 × 807.90cm²

= 403.95cm²

${\green{\boxed{\boxed{\bf{ area\:of\: triangle : {403.95cm}^{2}}}}}}$