Question

Percent by mass of solute in its aqueous solution is 28 and molar mass is 28 gram calculate the mole fraction and molality of the solute in the solution.

Answer 1

Answer: Mass of the aqueous solution is 28. Molar mass is 28. Therefore molality is 28/28 = 1.

We know the mole fraction of a solution is the ratio between the numbers of moles present in a component after made a solution to the total moles of all components in a solution.

Answer 2

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Answer :-
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➡️Given percent by mass = 28
that means in 100g of solution the mass of solute is 28g and therefore mass of solvent =100-28=72.

(taking the solvent to be water)
 
moles of solute = 28/28 = 1.                [mass/GMM]
moles of solvent = 72/18 = 4
 
therefore molefraction (X)= 1/(4+1)=1/5=0.2

molality (m)= (moles of solute/mass of solvent)*1000
                   =(1/72)*1000=13.88.
 

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