Question

(PERCENT BY VOLUME) What is the volume percent of ethanol in a mixture of 40 mL ethanol and 80 mL water (assume that the volume of solution is 120 mL

Answer 1

Answer:

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Explanation:

Volume of solute (ethanol): 40 ml

Volume of solvent (water): 100 ml

∴ Volume of solution = 40+100 = 140 ml  

Concentration = Volume of solute / Volume of solution

                       = 40 / 140  × 100

                      = 28.59 % (approx.)