Chemistry, asked by akhtarqhan786, 6 months ago

percent ionic character of Chcl3

Answers

Answered by mayank0541

0

Explanation:

μ

ionic

(ionicdipole)=4.8×10

−10

×1.275×10

−8

μ

ionic

=6.12×10

−18

esucm=6.12D

Observed dipole moment μ

observed

=1.032D

% ionic character =

μ

ionic

μ

observed

×100

=

6.12D

1.032D

×100

=16.38%

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