Question

Percent yield of NH3 in the following reaction is
80%
NH2CONH2 + 2NaOH-4 Na2CO3 + 2NH3
calculate weight of NH3 when 6 g NH CONH2 reacts
with 8 g NaOH.
o
3.4 g

Answer 1

Explanation:

We have

1 mole of urea is reacting with 2 mole of NaOH and give 2 mole of NH3

So, moles of urea = 606=0.1mol

So, 0.1 mole of urea will produce 0.2 mole of NH3

Moles of NH3 = 0.2 mol

Mass of NH3 produced  = 0.2∗17=3.4g

But the yield is 80%

So, amount of NH3 produced =  1003.4×80=2.7g

So, amount of NH3 produced = 3g