Question

percentage composition of Al in KAl(SO4)2•12H2O​

Answer 1

First calculate the Molar Mass of the given compound.

Atomic mass of -:

1) K = 39

2) Al = 27

3) S = 32

4) O = 16

5) H = 1

Now according to the compound given, the molar mass should be = (1*39) + (1*27) + (96*2) + (12*18)

= 458 g/mol

Now the percentage composition of Al is,

= molar mass of component / molar mass of the compound * 100

= 27 / 458 * 100

= 5.895%

Hope you got the solution :)