Chemistry, asked by Anonymous, 13 days ago

percentage composition of CaSO4 in CaSO4.2H2O

Answers

Answered by midhunmadhu1987
2

Answer:

79%

Explanation:

Mass of Ca = 40

Mass of Sulphur, S = 32

Mass of Oxygen, O = 16

Mass of CaSO₄ = 40 + 32 + (4 * 16) = 40 + 32 + 64 = 136 u

Mass of CaSO₄.2H₂O = 40 + 32 + (4 * 16) + 2(2 * 1 + 16) = 136 + 36 = 172 u

Mass percent of CaSO₄ in CaSO₄.2H₂O  =

Mass of CaSO₄ / Mass  of  CaSO₄.2H₂O * 100

= 136 / 172 * 100 = 79%

Similar questions