Question

percentage error in measurement of mass and velocity are plus minus 2% and plusminus 3% what will be the percentage energy in kinetic energy​

Answer 1

Answer:

Given percentage errors in mass and velocity = 2% and 3% respectively

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE =

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will be

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bem

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 v

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 vΔv

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 vΔv

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 vΔv ×100

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 vΔv ×100= 2+6

Given percentage errors in mass and velocity = 2% and 3% respectivelyThe kinetic energy of the particle is given by KE = 2mv 2 The percentage error in kinetic energy will bemΔm ×100+2 vΔv ×100= 2+6= 8%

Explanation:

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