Question

Percentage error in the measurements of radius of a sphere is 3%, then what is the error in measurement of surface area ?

Answer 1

Your answer is --

Given, % error in radius = 3%

Now, surface area S = 4πr^2

Since, 4π is constant and dimensionless

∆S/S×100 = ( 2× ∆r/r ) × 100

=> ∆S/S×100 = 2×3

=> ∆S/S×100 = 6%

Hence, % error in measurement of surface area of sphere is 6%

【 Hope it helps you 】

Answer 2

hey mate ur answer in attachment....