Question

Percentage errors in measurement of mass 1 percent and speed 2 percent. What is perecntage error in kinetic energy

Answer 1

Answer:

5%

Explanation:

K.E=1/2mv^2

∆K.E/K.E=∆m/m+2∆v/v

%error of kinetic energy=∆K/K×100

=∆m/m×100+2∆v/v×100

=1+2(2)

=5%

Thank you