Question

percentage ionisation of formic acid at 25 degree.
a) 0.086 M
b)1.75 M
​

Answer 1

Answer:

b) 1.75 M

Explanation:

b)

Ka = 1.7 * 10^-4 = X^2 / 1.75 - X

=> X = 0.0172

% dissociation = 0.0172 * 100 / 1.75 = 0.98 %

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Answer 2

Answer:

Answr - option b

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