Question

Percentage of ammonia in ammonium nitrate

Answer 1

Hey Friend,

Ammonium Nitrate - NH4NO3

Atomic weights -
1. N = 14
2. H = 1
3. O = 16

Therefore, molecular weight of NH4NO3..
= 14 + 4 + 14 + 48
= 80 g per mole

Molecular weight of NH4..
= 14 + 4
= 18 g per mole

percentage  =  molecular weight of element x number of atoms of                    composition     that element x 100 / molecular weight of compound

Therefore, 
%of NH4 in NH4NO3 = 18 x 1 x 100 / 80 
                                   = 22.5 %

Therefore, 22.5 % of NH4 is the answer.

Hope it helps!