percentage of carbon, hydrogen, nitrogen and oxygen are 62.07, 10.34, 14.0 and 13.59 respectively. if molecular mass is 114 , find molecular and empirical formula
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Explanation:
100 g of compound will contain 62.07 g of C, 10.34 g of H, 14.0 g of N and 13.59 g of O.
The atomic masses of C, H, N and O are 12 g/mol, 1 g/mol, 14 g/mol and 16 g/mol respectively.
The number of moles of C = 62.07g / 12g/mol = 5.17mol
The number of moles of H = 10.34g / 1g/mol = 10.34 mol.
The number of moles of N = 14g / 14g /mol = 1mol
The number of moles of O = 13.59 g / 16g/mol = 0.85 mol.
The mole ratio C:H:N:O=5.17:10.34:1:0.85≃5:10:1:1
Hence, the empirical formula is C5 H10 NO
The empirical formula mass =5(12)+10(1)+14+16=100 g/mol
The ratio of molecular formula mass to empirical formula mass = 144/100 = 1.44
Hence, the molecular formula of organic compound is ( C5 H10 NO)1.44
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