Percentage of nitrogen in urea expressed as
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Answered by
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46%
Urea = NH2-CO-NH2
Total mass = 60
Mass of nitrogen = 14 , 2 molecules, hence
m = 28
N% = mass of nitrogen / mass of urea × 100
=28/60 × 100
N% = 46.6
Urea = NH2-CO-NH2
Total mass = 60
Mass of nitrogen = 14 , 2 molecules, hence
m = 28
N% = mass of nitrogen / mass of urea × 100
=28/60 × 100
N% = 46.6
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0
Answer:
46
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