Question

Percentage of oxygen in urea

Answer 1

Answer:

urea=> NH₂-CO-NH₂

total mass=60

mass of oxygen 'O₂' ==> 16 x 2 = 32

O% = mass of oxygen x 100

mass of urea - 60

===> $\frac{32 X 100}{60}$ =( 53.3%) O₂

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