Question

percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. Wt.=78.4) then minimum molecular weight of peroxidase anhydrous enzyme is
A) 1.568 x 10*2 B) 1.568 x 10*3
C) 15.68 D) 2.136 x 10*4

Answer 1

Answer:

A

Explanation:

Correct option is A

1.568×10^4

In peroxidase anhydrous enzyme, 0.5 gm Se is present in 100gm of the enzyme.

In a molecule of enzyme, one Se atom must be present.

Hence 78.4gm Se will be present in 100/0.5×78.4=1.568×10^4

Hence, the correct option is A.