Question

Percentage of sodium catbonate

Answer 1

Answer:

5%

Explanation:

+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++=======

Answer 2

Answer:

Formula: Na2CO3

Na Molecular Mass: 22.98 grams

C Molecular Mass= 12.01 grams

O Molecular Mass= 16 grams

Now, the molecular mass of the compound: 2(22.98) + 12.01 + 3(16)= 105.97 grams

Now, when you do percent composition all you are doing is this: Amount of Element in Grams/ Total Compound Mass in Grams x 100%.

So, lets do that for each of these elements:

Na:

105.97

2×22.98

×100%=43.37%

C:

105.97

12.01

×100%=11.33%

O:

105.97

3×16

×100%=45.30%

Now, add up these percentages and make sure that they add up to exactly 100%.

43.37% + 11.33% + 45.30%= 100.00 %