percentage pass mark in Sainik School entrance exam is 40% a boy gets 60% and fails by 80 marks find the maximum marks
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From 100% he loses 40%.
He also losses 80 marks.
This means that after losing 80 marks his percentage is reduced by 40%.
If 40%=80
Then, 1%=80/40
1%=2
100%=200.
Therefore, maximum marks is 200.
Answered by
0
Answer:
200
Step-by-step explanation:
60+80=140
40x×=140×100
40x=14000
x=14000/40=350
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