Question

perdict the position of the element[period and group] of the element in periodic table satisfying the electronic configuration [n-1]d2 ns2 where n =5​

Answer 1

Explanation:

Here outer most electron enters into the 3d hence the element belongs to d−block, number of group for d−block element= no. of electrons in (n-1)orbital + no. of electrons in n orbital=2+1=3 hence, the element belongs to 3rd group. Here principal quantum number is equal to the period of the element hence the element belongs to 4th period.