Math, asked by nishitag7588, 10 hours ago

Peremeter of a rectangle is 70 cm and its area 300cm fing leng and bredth

Answers

Answered by sadnesslosthim
15

Answer:

The dimensions of the rectangle are 15 and 20cm.

____________

Explanation:

Given that: Perimeter of a rectangle is 70 cm

Area of the rectangle is 300 cm.

Need to find: Length and Breadth

Concept:

Perimeter of a triangle = 2( l + b )

Area of rectangle = l × b

Where,

  • L denotes length
  • B denotes breadth

____________

Solution :

~By putting the values in the formula of finding perimeter.

\sf :  \implies Perimeter = 70 ; cm

\sf :  \implies  2( l + b) = 70

\sf :  \implies l + b = \dfrac{70}{2}

\sf : \implies l + b = 35

\sf \leadsto b = 35 - l

____________

~By putting the values in the formula of finding area.

\sf :  \implies Area = 300  cm

\sf :  \implies l × b = 300 cm

 \sf : \implies l × ( 35 - l ) = 300

\sf :  \implies 35l - l^{2} = 300

\sf : \implies 35l - l^{2} - 300 = 0

\sf : \implies l^{2} - 20l - 15l - 300 = 0

\sf : \implies l( l - 20 ) - 15( l - 20 ) = 0

\sf : \implies ( l - 20 )( l - 15 ) = 0

\sf : \implies l - 20 = 0

\sf : \implies l - 15 = 0

\sf \leadsto l = 20

\sf \leadsto l = 15

\sf : \implies b = 35 - l

\sf \leadsto b = 20

\sf \leadsto b = 15

~As taken as general, length is bigger tha breadth. So, we will consider length as 20 cm and breadth as 15 cm.

\boxed{\bf{  l = 20 cm}}  \star

\boxed{\bf{ b = 10  cm}}  \star

Similar questions