Question

Perfect answer will be marked as brainliest​

Answer 1

H

2

+

2

1

O

2

⟶H

2

O

Mass-4g20g

Moles-20.625

1 mole of H

2

requires 0.5 moles of O

2

.

∴ 1.25 moles of H

2

requires 0.625 moles of O

2

∴ O

2

is a limiting reagent.

0.5 mole O2

⟶1 mole H 2O

∴0.625 mole O

2 = 0.5

1×0.625

moles H 2

O =1.25 moles of H2O

Therefore, mass of H

2

O formed =1.25×18=22.5 gm