Perfect answer with steps for brainy tag!!! A force of 100N is acting on a surface of area 4m2 ( means 4 metre power 2). If the force is doubled and the area of the surface is made half of the initial area, what would be the difference in the pressure?
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Initial force (F) = 100N
Initial area (A) = 4 m2
Initial pressure (P) = 25 Pa
New force (F') = 2F = 200N
New area (A') = A/2 = 2 m2
New pressure (P') = F'/A' = 100Pa
Difference in pressure = 75 pa
Initial area (A) = 4 m2
Initial pressure (P) = 25 Pa
New force (F') = 2F = 200N
New area (A') = A/2 = 2 m2
New pressure (P') = F'/A' = 100Pa
Difference in pressure = 75 pa
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