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How to find Oxidation no. of
an element by their compound ?
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Answers
Before you understand oxidation no. first we know about oxidation:-
A substance can said to be oxidized if :-
1. It gains oxygen and loss hydrogen.
2. Increasment in ratio of electronegative radical or decreasment in ratio of electropositive radical.
3. Loss of electrons by species.
The oxidation number of a free element is always 0.
The oxidation number of a free element is always 0.The oxidation number of a monatomic ion equals the charge of the ion.
- The oxidation number of
The oxidation number of H
The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of
The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O
The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.The oxidation number of a Group 1 element in a compound is +1.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.The oxidation number of a Group 1 element in a compound is +1.The oxidation number of a Group 2 element in a compound is +2.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.The oxidation number of a Group 1 element in a compound is +1.The oxidation number of a Group 2 element in a compound is +2.The oxidation number of a Group 17 element in a binary compound is -1.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.The oxidation number of a Group 1 element in a compound is +1.The oxidation number of a Group 2 element in a compound is +2.The oxidation number of a Group 17 element in a binary compound is -1.The sum of the oxidation numbers of all of the atoms in a neutral compound is 0.
- The oxidation number of H is +1, but it is -1 in when combined with less electronegative elements.The oxidation number of O in compounds is usually -2, but it is -1 in peroxides.The oxidation number of a Group 1 element in a compound is +1.The oxidation number of a Group 2 element in a compound is +2.The oxidation number of a Group 17 element in a binary compound is -1.The sum of the oxidation numbers of all of the atoms in a neutral compound is 0.The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
Now take eg:- in K2Cr2O7.
in K2Cr2O7.Let oxidation number of Cr be 'x' then,
in K2Cr2O7.Let oxidation number of Cr be 'x' then,Oxidation number of K is +1 and that of O is -2 then,
in K2Cr2O7.Let oxidation number of Cr be 'x' then,Oxidation number of K is +1 and that of O is -2 then,2*1+2*x+7*-2=0
in K2Cr2O7.Let oxidation number of Cr be 'x' then,Oxidation number of K is +1 and that of O is -2 then,2*1+2*x+7*-2=0Solving the equation, we get x=6.
in K2Cr2O7.Let oxidation number of Cr be 'x' then,Oxidation number of K is +1 and that of O is -2 then,2*1+2*x+7*-2=0Solving the equation, we get x=6.This means oxidation number of Cr is 6.
Hope it helps!!