Question

perfect square
x²+x+1+2k (a ² x-1)=0 is
for how many values of k​

Answer 1

Answer:

Now, x2+x+1+2kx2−2kx−2k=0

(1+2)x2+(1−2k)x+(1−2k)=0 ____ (1)

Now, (ax+b)2=a2x2+b2+2abx

Comparing with (1)

2(1−2k)(1+2k)=(1−2k)

4(1−4k2)=1+4k2−4k

4−16k2=1+4k2−4k

20k2−4k−3=0

k=404±16+240

k=21 or 10−3